x^2+4x+6=x+2

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Solution for x^2+4x+6=x+2 equation:



x^2+4x+6=x+2
We move all terms to the left:
x^2+4x+6-(x+2)=0
We get rid of parentheses
x^2+4x-x-2+6=0
We add all the numbers together, and all the variables
x^2+3x+4=0
a = 1; b = 3; c = +4;
Δ = b2-4ac
Δ = 32-4·1·4
Δ = -7
Delta is less than zero, so there is no solution for the equation

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